A mass in the diagram below undergoes simple harmonic When the mass reaches point x = +A its instantaneous velocity is:

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A mass in simple harmonic motion (SHM) moves between -A and +A with its velocity depending on position. In SHM, the velocity is maximum when the displacement is zero (x = 0) and goes to zero at the turning points (x = ±A).

Option 1: 'Maximum and negative' — This would imply a nonzero velocity at x = +A, which contradicts the turning-point condition in SHM where velocity is zero at the extremes. Therefore this is incorrect.

Option 2: 'Maximum and positive' — Similar to option 1, it asserts a nonzero velocity at x = +A. At the extreme right, the mass momentarily stops before reversing direction, so velocity is not maximum here. This is incorrect.

Option 3: 'Zero' — This matches the key property of SHM: at the turning point x = +A, the velocity is zero because the mass changes direction there. This is the correct description of the instantaneous velocity at that position.

Option 4: 'Less than maximum' — While velocity is less than maximum at most positions, at x = +A the velocity is actually zero (the minimum possible magnitude in SHM), not merely less than the maximum value. This makes the statement incorrect.

In summary, the only statement consistent with SHM at the displacement x = +A is that the instantaneous velocity is zero, since the mass is momentarily at rest at the turning point.

SPHY001 Practice Quiz - Unit 16 | LA056

A mass in the diagram below undergoes simple harmonic When the mass reaches point x = +A its instantaneous velocity is:

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