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Short answer

Given the Lewis structure below:  There are [Blank-1] sigma bonds and [Blank-2] pi bonds.

Options
A.Blank # 1
B.Blank # 2
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Step-by-Step Analysis
To solve this, we need to count the sigma and pi bonds in the given Lewis structure. Option analysis for Blank # 1 (sigma bonds): - The leftmost H–C bond is a sigma bond: 1 sigma. - The C≡C triple bond consists of 1 sigma bond plus 2 pi bonds: 1 sigma here. - The single bond between the second and third carbon (C–C) is a sigma bond: 1 more. - The third ......Login to view full explanation

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