Questions
Short answer
Given the Lewis structure below: There are [Blank-1] sigma bonds and [Blank-2] pi bonds.
Options
A.Blank # 1
B.Blank # 2
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Step-by-Step Analysis
To solve this, we need to count the sigma and pi bonds in the given Lewis structure.
Option analysis for Blank # 1 (sigma bonds):
- The leftmost H–C bond is a sigma bond: 1 sigma.
- The C≡C triple bond consists of 1 sigma bond plus 2 pi bonds: 1 sigma here.
- The single bond between the second and third carbon (C–C) is a sigma bond: 1 more.
- The third ......Login to view full explanationLog in for full answers
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