If three resistors are all connected in series, find the total resistance in the circuit. R1 = 86Ω, R2 = 84Ω and R3 = 51Ω. Only put in the numerical value. Do not write the unit in your answer.

Question

If three resistors are all connected in series, find the total resistance in the circuit. R1 = 86Ω, R2 = 84Ω and R3 = 51Ω. Only put in the numerical value. Do not write the unit in your answer.

BlackTom AI · Accepted Answer

The problem involves resistors connected in series, where the total resistance is the sum of the individual resistances.
First, identify the given values: R1 = 86 Ω, R2 = 84 Ω, R3 = 51 Ω.
In a series circuit, resistances simply add up: R_total = R1 + R2 + R3.
Compute the sum step by step: 86 + 84 = 170, then 170 + 51 = 221.
Therefore, the total resistance of the circuit is the sum of the three resistors, which equals 221.
Note: Since the instruction asks not to write the unit in the answer, ensure that only the numerical value 221 is provided in the response field.

If three resistors are all connected in series, find the total resistance in the circuit. R1 = 86Ω, R2 = 84Ω and R3 = 51Ω. Only put in the numerical value. Do not write the unit in your answer.

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If three resistors are all connected in series, find the total resistance in the circuit. R1 = 86Ω, R2 = 84Ω and R3 = 51Ω. Only put in the numerical value. Do not write the unit in your answer.

View Explanation

Log in for full answers

Similar Questions

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More Practical Tools for Students Powered by AI Study Helper

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I have a simple circuit running off a battery powering a lightbulb (bulb A). If I add another light (bulb B) in series with bulb A I can expect that the voltage across bulb A will _ and bulb A will shine___.