Compared to the current in R1, the current in R2 is

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BlackTom AI · Accepted Answer

In this circuit, the components R1, R2, and R3 are arranged in a single loop with the 15-volt source, so the current is the same through all series elements. 
First, note the given current in the bottom branch through R3 is 0.50 A; since it is a series circuit, that same current must flow through R1 and R2 as well.
To verify, compute the total resistance using Ohm's law: R_total = V / I = 15 V / 0.50 A = 30 Ω.
The sum of the known resistances is R1 + R3 = 5 Ω + 15 Ω = 20 Ω, leaving R2 = 30 Ω − 20 Ω = 10 Ω, which is consistent with a single loop carrying 0.50 A.
Thus, the current in R2 equals the current in R1, which is 0.50 A, so the currents are the same across these resistors.

Physics 1 Hon - Bowles - p06/p07 P10.13/10.15 Electrostatics & Circuits MC Practice

Compared to the current in R1, the current in R2 is

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Physics 1 Hon - Bowles - p06/p07 P10.13/10.15 Electrostatics & Circuits MC Practice

Compared to the current in R1, the current in R2 is

View Explanation

Log in for full answers

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