If you execute the following code one line at a time, R will return 5.

Hint: There are some restrictions
Links to an external site.
on how you can name an object in R.

a

Question

If you execute the following code one line at a time, R will return 5.

Hint: There are some restrictions
Links to an external site.
 on how you can name an object in R.

a <- 3

b <- 2

else <- 2 * (a + b)

else / 2

BlackTom AI · Accepted Answer

The question asks us to consider what R would return when executing the given code line by line, noting there are naming restrictions for objects in R.
Option 1: True. This would imply that the code yields 5. However, the critical issue here is the object name 'else'. In R, 'else' is a reserved word used in control flow (if... else). As a result, trying to assign to a variable named else without backticks is not allowed, and the code will fail at the line else <- 2 * (a + b). Therefore, the statement that R will return 5 is incorrect because the naming restriction prevents successful execution of that line, so you do not even reach the final division by 2 to produce 5.
Option 2: False. This statement claims that the code does return 5. The main obstacle is the invalid object name 'else'. Since 'else' is reserved, the assignment will produce a syntax/parse error before the calculation can complete, so the code cannot return 5 as written. This aligns with the idea that the claim is not true given the naming rule.
Additional nuance: if you really wanted to use a name that looks like a keyword, you could backtick the name, e.g., `else` <- 2 * (a + b); then evaluating else / 2 would yield 5. But without backticks, the code as provided cannot execute successfully, so the overall statement that it returns 5 is false.
In short, the restriction on naming is the decisive factor, making the True option incorrect and the False option correct in the sense of the code as written.

COMM_V 205 101 102 103 2025W1 In-class Exercise (ICE) 8

If you execute the following code one line at a time, R will return 5. Hint: There are some restrictions Links to an external site. on how you can name an object in R. a <- 3 b <- 2 else <- 2 * (a + b) else / 2

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