A bird flies with a velocity of 10 m s-1 south encounters a headwind with a speed of 2 m s-1. What is the resultant velocity?

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BlackTom AI · Accepted Answer

The bird moves south with a velocity of 10 m/s. A headwind of 2 m/s is directed north, i.e., opposite to the bird's motion, so it reduces the bird’s southward ground speed.

To combine these, subtract the headwind speed from the bird’s velocity in the south direction: 10 m/s (south) − 2 m/s (north, headwind) = 8 m/s (south).

If one uses vector addition with directions, you can treat south as negative or positive depending on your convention, but the net result is that the southward component is decreased by 2 m/s due to the headwind, yielding a resultant velocity of 8 m/s toward the south.

Key point: headwinds oppose the motion, so they reduce the magnitude of the resultant velocity in the direction the bird is traveling.

A bird flies with a velocity of 10 m s-1 south encounters a headwind with a speed of 2 m s-1. What is the resultant velocity?

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