What is the value stored to str?string str = "HP No: 93567881, IC No:S9875812W and admin number: 140007X";Match m;m = Regex.Match(str, @"[a-zA-Z]*([\d]+[A-Z])");str = m.Groups[1].Value;

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BlackTom AI · Accepted Answer

The task presents a short-answer scenario with a given string and a regular expression, asking what value is stored to str after the substitutions.
First, note the input string: "HP No: 93567881, IC No:S9875812W and admin number: 140007X".
Then examine the regex used: @"[a-zA-Z]*([\d]+[A-Z])". This pattern consists of:
- [a-zA-Z]*: zero or more letters at the start (this part is not captured).
- ([\d]+[A-Z]): a capturing group that must contain one or more digits followed by a single uppercase letter. The digits are captured, and the final uppercase letter is included as part of the capturing group.
Next, apply the regex to the string to locate a substring that fits the pattern and capture the digits plus the following uppercase letter:
- The segment "S9875812W" matches: it has the letter S, then digits 9875812, followed by the uppercase letter W. The capturing group therefore captures "9875812W".
- A prior segment like "93567881" lacks a trailing uppercase letter after the digits, so it does not satisfy the capturing group requirement.
Consequently, the match produced by m.Groups[1].Value will be the string "9875812W".
Finally, str is assigned the value of that capturing group, so str becomes "9875812W".
Note: If there were multiple possible matches, the Regex.Match method would return the first match in the string, but in this input, the first valid capturing group that satisfies [\d]+[A-Z] appears in the portion S9875812W, yielding the captured value 9875812W.

What is the value stored to str?string str = "HP No: 93567881, IC No:S9875812W and admin number: 140007X";Match m;m = Regex.Match(str, @"[a-zA-Z]*([\d]+[A-Z])");str = m.Groups[1].Value;

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What is the value stored to str?string str = "HP No: 93567881, IC No:S9875812W and admin number: 140007X";Match m;m = Regex.Match(str, @"[a-zA-Z]*([\d]+[A-Z])");str = m.Groups[1].Value;

View Explanation

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