The average rate of disappearance of ethane (C2H6) in the reaction,

2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)

is found to be 1.50
×
10–3 M·s–1 over a certain interval of time. What is the rate of appearance of H2O during this time interval?

Question

The average rate of disappearance of ethane (C2H6) in the reaction,

2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)

is found to be 1.50 
×
 10–3 M·s–1 over a certain interval of time.  What is the rate of appearance of H2O during this time interval?

BlackTom AI · Accepted Answer

The question concerns the relationship between the rates of appearance/disappearance of species in a stoichiometric reaction. The given reaction is: 2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(g).

First, identify the stoichiometric coefficients that relate C2H6 to H2O. For every 2 moles of C2H6 that disappear, 6 moles of H2O are formed. Therefore, the rate of appearance of H2O is (6/2) times the rate of disappearance of C2H6.

Compute the factor: 6/2 = 3. If the average rate of disappearance of C2H6 is 1.50 × 10^−3 M/s, multiply by 3 to obtain the rate of appearance of H2O:
1.50 × 10^−3 M/s × 3 = 4.50 × 10^−3 M/s.

Now compare with the provided option. The option given is 4.50 × 10^−3 M·s^−1, which matches the calculated value exactly.

Why the other options (if any) would be incorrect: since there is only one option listed here, there are no other choices to evaluate. If there were alternative numeric values, you would check them against the 3:1 ratio derived from the 2:6 (or 1:3) stoichiometry and ensure unit consistency (M/s) to determine correctness.

The average rate of disappearance of ethane (C2H6) in the reaction, 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g) is found to be 1.50 × 10–3 M·s–1 over a certain interval of time. What is the rate of appearance of H2O during this time interval?

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