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Question text 5Marks Question 23 (5 marks)Experiments were conducted to determine the rate law for the nucleophilic substitution reaction between chloromethane and sodium hydroxide.CH3Cl + OH— → CH3OH + Cl—The Rate Law expression is given by: Rate = k [CH3Cl]X [OH—]YThe following rates were obtained in the experiments.A. The nucleophile in the reaction is Answer 1[select: , chloromethane, hydroxide ion, methanol, chloride ion]B. The order with respect to CH3Cl is Answer 2[select: , 0, 1, 2, 3]C. The overall order of the reaction is Answer 3[select: , 0, 1, 2, 3]D. The value of the rate constant is Answer 4[select: , 5, 10, 50, 100]E. A fourth experiment is carried out using 0.20 M CH3Cl and 0.30 M OH—. What is the rate of formation of methanol? (M s-1) Answer 5[select: , 3, 0.30, 0.60, 0.90](1 + 1 + 1 + 1 + 1 = 5 marks)Notes Report question issue Question 23 Notes

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Question restatement and options: A. The nucleophile in the reaction is [select: hydroxide ion, chloromethane, methanol, chloride ion] B. The order with respect to CH3Cl is [select: 0, 1, 2, 3] C. The overall order of the reaction is [select: 0, 1, 2, 3] D. The value of the rate constant is [select: 5, 10, 50, 100] E. A fourth experiment is carried out using 0.20 M CH3Cl and 0.30 M OH−. What is the rate of formation of methanol? (M s−1) [select: 3, 0.30, 0.60, 0.90] Step-by-step analysis of the data and each option: - Option A (The nucleophile in the reaction is ...): From the reaction given, CH3Cl + OH− → CH3OH + Cl−, the nucleophile is the species that donates the pair to attack the carbon. In this reaction......Login to view full explanation

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