Questions
CHEM 110 Lecture Quiz Week 6
Single choice
A proposed mechanism for the reaction 2O3 ---> 3O2 is shown below. NO + O3 ---> NO2 + O2 (slow) NO2 + O3 ---> NO + 2O2 (fast) What is the rate law consistent with this mechanism?
Options
A.rate = k[NO][O3]
B.rate = k[NO2][O3]
C.rate = k[NO][O3]2[NO2]
D.rate = k[O3]2
View Explanation
Verified Answer
Please login to view
Step-by-Step Analysis
Begin by identifying the rate-determining step in the provided mechanism. The slow step is NO + O3 -> NO2 + O2, which means the overall reaction rate is controlled by this step.
Option 1: rate = k[NO][O3]. This directly matches the rate expression for the slow, elementary step, since the rate depends on the concentrations ......Login to view full explanationLog in for full answers
We've collected over 50,000 authentic exam questions and detailed explanations from around the globe. Log in now and get instant access to the answers!
Similar Questions
Rate constants have units of .
The following question(s) relate to the reaction between water and a complex ion of Co2+; the rate varies with concentration as follows. (The rate has no dependence on [H2O].) Trial [Co2+ complex], M Initial rate, M min−1 1 1.14 × 10−3 3.2 × 10−7 2 2.28 × 10−3 6.4 × 10−7 3 3.42 × 10−3 9.6 × 10−7 4 1.14 × 10−2 3.2 × 10−6 Refer to Exhibit 11-1. The rate law for the reaction is rate =
Consider the reaction NO2 + O3 NO3 + O2 Use the data shown to determine the rate law for the reaction. Experiment [NO2] M [O3] M Rate M s−1 1 0.21 0.70 6.30 x 10−3 2 0.63 0.70 1.89 x 10−2 3 0.21 0.35 3.15 x 10−3 4 0.42 0.35 6.30 x 10−3
Nitrogen dioxide decomposes via the following reaction, NO2(g) → NO(g) + 1/2O2(g) The experimental rate law is rate = k[NO2]2. At a specific temperature the rate of reaction was found to be 7.50 x 10-4 mol L-1 s-1. Which unit below is the correct unit for the rate constant in this case?
More Practical Tools for Students Powered by AI Study Helper
Making Your Study Simpler
Join us and instantly unlock extensive past papers & exclusive solutions to get a head start on your studies!