Question at position 2 What will the following code print? print("A", "B", "C", sep=":", end=".")A:B:C.A:B:CA B C.A.B.CClear my selection

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Question at position 2 What will the following code print? print("A", "B", "C", sep=":", end=".")A:B:C.A:B:CA B C.A.B.CClear my selection

BlackTom AI · Accepted Answer

Here’s the question restated: What will the following code print? print("A", "B", "C", sep=":", end=".")

Now, examine each answer option against how Python’s print function behaves with the given arguments.

Option 1: "A:B:C."
- This aligns with the behavior of print when you specify sep=":". The arguments "A", "B", and "C" will be separated by colons, producing "A:B:C". The parameter end="." adds a trailing period after the printed content, yielding "A:B:C.". This option matches the actual output.

Option 2: "A:B:C"
- Here, the string ends without a final punctuation mark. This would occur if end were an empty string (end=""), but in the code end is explicitly set to ".". Therefore, the missing trailing period makes this option incorrect.

Option 3: "A B C."
- This would be the result if sep used the default space (" ") and there were a final period added by end=".". Since sep is set to ":", the spaces between letters do not appear, so this option does not reflect the actual separation.

Option 4: "A.B.C"
- This would require sep to be a period (sep="."), which is not the case here. With sep=":", periods do not appear between the letters, so this option is incorrect.

In summary, the combination of sep=":" and end="." produces the exact string described in Option 1, while the other options rely on different sep or end values that do not match the given code.

Question at position 2 What will the following code print? print("A", "B", "C", sep=":", end=".")A:B:C.A:B:CA B C.A.B.CClear my selection

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