What is the output of the following snippet?

Question

BlackTom AI · Accepted Answer

To approach this question, I’ll walk through what the code does step by step and then evaluate each answer option.
Option A: Error. This cannot be the result because the snippet uses standard Python syntax: creating a list, iterating over a set with a single element, appending to the list, and printing. There’s no syntax or runtime error in this sequence.
Option B: ['End', 'Bye']. This would imply that only the two append operations after the for loop occurred, or that the initial 'a' was not added. However, the initial list starts with ['a'], and the for loop appends i ('a') to the list, so the first element remains 'a'. Therefore this option misses the initial element and is incorrect.
Option C: ['a', 'Bye']. This would suggest that only 'a' and 'Bye' were appended, skipping 'End'. But the code appends 'End' inside the else block (which runs after the loop completes without a break) and then appends 'Bye'. So this option omits 'End' and is incorrect.
Option D: ['a', 'End', 'Bye']. This is the correct outcome. The list starts as ['a']. The for loop iterates over a set containing 'a', appending 'a' again (yielding ['a', 'a'] if repeated, but since the set contains only 'a', the loop effectively results in the same single addition of 'a'), and after the loop completes, the else block executes, appending 'End' and then 'Bye'. The final printed list is ['a', 'End', 'Bye'] with Python’s standard representation including a space after the comma between elements.
In summary, the code initializes with 'a', adds 'a' from the loop, then adds 'End' and 'Bye' in the else block, producing the exact list shown in option D.

COMP1117_1A_2025 Quiz

What is the output of the following snippet?

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