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Questions
Multiple choice
Question at position 1 In this lab, you will directly measure physical quantities to deduce a ball's launch speed. Which physical quantities will you directly measure? Select all choices that are true. The ball's launch velocityThe maximum angle the pendulum swings outThe maximum height that the pendulum reaches above the tableThe total mass of the spring launcherThe mass of the ballThe acceleration due to gravityThe range of the ballThe distance between the motion sensor and the spring launcherThe time it takes the ball to transit the two photogatesI will not measure any of the quantities listed above directly.
Options
A.The ball's launch velocity
B.The maximum angle the pendulum swings out
C.The maximum height that the pendulum reaches above the table
D.The total mass of the spring launcher
E.The mass of the ball
F.The acceleration due to gravity
G.The range of the ball
H.The distance between the motion sensor and the spring launcher
I.The time it takes the ball to transit the two photogates
J.I will not measure any of the quantities listed above directly.
View Explanation
Standard Answer
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Approach Analysis
The question asks which physical quantities will be directly measured in the lab to deduce a ball's launch speed, given a list of possible quantities. We'll evaluate each option one by one and explain why it would or would not be directly measured.
Option: The ball's launch velocity
- Direct measurement: In many setups, the launch velocity is not measured directly at the moment of launch; instead, other quantities (like time-of-flight, distance, or sensor readings) are measured and used to infer the launch speed. Thus, this option is not typically a quantity you would directly measure in this experiment.
Option: The maximum angle the pendulum swings out
- Direct measurement: If a pendulum is part of the launcher mechanism, you might observe how far the pendulum swings during calibration or setup. However, the maximum swing angle is not necessarily used to deduce the ball's launch speed i......Login to view full explanationLog in for full answers
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