Consider the following planning problem in PDDL

Init(At(P1,A),At(P2,B),At(P3,C),At(P4,D),At(P5,E),Pipe(P1,P3),Pipe(P3,P5),Pipe(P5,P2),Pipe(P2,P4),Pipe(P4,P1))

Goal(At(P1,D),At(P2,C),At(P3,A),At(P4,E),At(P5,B))

Action(Jump(x,from,to)

PRECOND:At(from,x)∧Pipe(from,to)
EFFECT:¬At(from,x)∧At(to,x))

At which level of the planning graph does the literal At(P5,A) appear for the first time?

Question

Consider the following planning problem in PDDL

Init(At(P1,A),At(P2,B),At(P3,C),At(P4,D),At(P5,E),Pipe(P1,P3),Pipe(P3,P5),Pipe(P5,P2),Pipe(P2,P4),Pipe(P4,P1))

Goal(At(P1,D),At(P2,C),At(P3,A),At(P4,E),At(P5,B))

Action(Jump(x,from,to)

PRECOND:At(from,x)∧Pipe(from,to)
EFFECT:¬At(from,x)∧At(to,x))

At which level of the planning graph does the literal At(P5,A) appear for the first time?

BlackTom AI · Accepted Answer

First, restate the problem: we have an initial state with At(P1,A), At(P2,B), At(P3,C), At(P4,D), At(P5,E), and a set of pipes: P1→P3, P3→P5, P5→P2, P2→P4, P4→P1. The Jump action moves an object x from a location 'from' to a location 'to' when At(from, x) holds and there is a Pipe(from, to). The question asks when the literal At(P5,A) can appear for the first time in the planning graph.

Option evaluation:
Option: Level S2.
- Step-by-step reasoning:
  1) At time zero (S0), the initial facts include At(P1,A). This means A is located at P1 at the start.
  2) To make At(P5,A) true, we need to move A along a path from its current location to P5, using Jump actions along available pipes.
  3) From P1, the only outgoing pipe is P1→P3. Since At(P1,A) holds at S0, the Jump(A, from=P1, to=P3) action is enabled, because the precondition At(from, x) is satisfied and Pipe(P1, P3) exists. Executing this jump yields At(P3,A) and no longer At(P1,A); this result becomes available at level S1.
  4) At S1, with A now at P3, there is a pipe P3→P5. The Jump(A, from=P3, to=P5) action is enabled (At(P3,A) holds and Pipe(P3,P5) exists). Executing this jump moves A from P3 to P5, giving At(P5,A). This culminates in the new fact appearing at level S2.
  5) Therefore, the first introduction of At(P5,A) occurs after two successive Jump actions, i.e., at level S2 in the planning graph.

Why other potential misinterpretations are incorrect:
- If one argued that At(P5,A) could appear in S1, that would require At(P3,A) to be present in S0, which it is not; A starts at P1 and only moves to P3 in S1 after applying Jump(A, P1, P3).
- If one insisted there were an alternative path from P1 to P5 without passing through P3, the given pipes do not provide such a direct route; every route to P5 must go P1→P3 and then P3→P5, given the exact pipe relations provided.
- Any claim that At(P5,A) is already true in S0 is false because At(P5,E) is the initial fact for P5, not At(P5,A).

In summary, the literal At(P5,A) first appears at level S2, following the two-step sequence Jump(A, P1, P3) then Jump(A, P3, P5).

DD2380 HT24 (AIHT24_2) Q9: Planning

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