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Question at position 2 If z=yx2+6yz=y\sqrt{x^2+6y}, then ∂z∂y=\frac{\partial z}{\partial y\:}= yx2+6y+x2+6y\frac{y}{\sqrt{x^2+6y}}+\sqrt{x^2+6y}3yx2+6y\frac{3y}{\sqrt{x^2+6y}}3yx2+6y+x2+6y\frac{3y}{\sqrt{x^2+6y}}+\sqrt{x^2+6y}(2x+6)yx2+6y\left(2x+6\right)y\sqrt{x^2+6y}x2+6y\sqrt{x^2+6y}
Options
A.𝑦
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B.3
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C.3
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E.𝑥
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Step-by-Step Analysis
We begin by clearly restating what is being asked: a question about the derivative ∂z/∂y for a relationship involving z, y, and x, where z is defined implicitly via z = yx^2 + 6yz = y√(x^2 + 6y). Now we evaluate each answer choice in turn to see which expression for ∂z/∂y aligns with the given relation.
Option 1: y x^2 + 6 y + x^2 + 6 y
- This option combines two straightforward terms, x^2 y and 6y, with an extra x^2 and another 6y. The appearance of an isolated x^2 term (without y) suggests it does not consistently reflect a derivative that should depend on z or on the structure of the original equation. In particular, unless there is a reason for x^2 to appear unmultiplied by y or z in the derivative, this form seems unlikely to be th......Login to view full explanationLog in for full answers
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