Question textThe diagram shows a courier in a lift who is delivering a box. When the lift is accelerating upwards, F1 is Answer 1 Question 3[select: , , =, , =, , =, , =, , =,

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Question textThe diagram shows a courier in a lift who is delivering a box. When the lift is accelerating upwards, F1 is Answer 1 Question 3[select: , >, =, <] F2. When the lift is accelerating downwards, F1 is Answer 2 Question 3[select: , >, =, <] F2. When the lift is at rest, F1 is Answer 3 Question 3[select: , >, =, <] F2. When the lift is moving upwards at a constant velocity, F1 is Answer 4 Question 3[select: , >, =, <] F2. When the lift is moving downwards at a constant velocity, F1 is Answer 5 Question 3[select: , >, =, <] F2.

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The scenario involves a box inside a lift with two forces acting on it along the vertical: F1, which is drawn as an upward force on the box, and F2, drawn as a downward force (gravity). The key idea is to compare F1 with F2 under different elevator motions to infer the relative magnitudes. Option 1 (upward acceleration of the lift): Here the box experiences an upward acceleration. To produce an upward net force equal to m a, the upward force F1 must exceed the downward gravitational force F2. Therefore F1 > F2. Option 2 (downward acceleration of the lift): In this case the box accelerates downward, so the net force points downward and the upward force F1 must be smaller than the downward force F2 to yield m a downward. Thus F1 < F2. Option 3 (lift at rest): When the lift is stationary, the box experiences no vertical acceleration. The forces must balance, so the upward force equals the downward force: F1 = F2. Option 4 (lift moving upward at constant velocity): Constant velocity means zero acceleration. The forces balance just as in rest, so F1 = F2. The speed of the lift does not affect the balance of forces when acceleration is zero. Option 5 (lift moving downward at constant velocity): Similar reasoning to option 4; zero acceleration implies F1 = F2. The constant velocity does not change the balance of forces on the box. In summary, the comparative relations are: > for upward acceleration, < for downward acceleration, and = for rest or constant-velocity motion. Each choice aligns with the basic dynamics F1 − F2 = m a, where a is the lift's acceleration and F2 represents gravity.

MUF0121 Physics Unit 1 - Semester 2, 2025 4.13 Newton's Third Law

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