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MCD2130 - T2 - 2025 Lecture Task Week 7

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Question text Find trigonometric ratios of the angle [math: θ]\theta in the right-angled triangle [math: △ABC]\triangle ABC. (diagram is not to scale)[math: a=20,b=48,c=52]a={20}, b={48}, c={52} Note: Write your answers as a fraction [math: p]/[math: q]. [math: sin⁡(θ)=]\sin(\theta)= [input] [math: 2052] \frac{20}{52} Correct answer. Well done. [math: cos⁡(θ)=]\cos(\theta)= [input] [math: 4852] \frac{48}{52} Correct answer. Well done. [math: tan⁡(θ)=]\tan(\theta)= [input] [math: 2048] \frac{20}{48} Correct answer. Well done.

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The task involves finding the trigonometric ratios for the angle θ in the right-angled triangle △ABC with side lengths a = 20, b = 48, c = 52 where c is the hypotenuse. To reason through this, recall the standard definitions: sine is opposite over hypotenuse, cosine is adjacent over hypotenuse, and tangent is opposite over adjacent. First, consider sin(θ).......Login to view full explanation

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