Questions
BN5206 Week 10 online quiz
Single choice
Consider the following second-order ODE ๐ 2 ๐ฆ ๐ ๐ฅ 2 = ๐ฅ + ๐ฆ + ๐ ๐ฆ ๐ ๐ฅ Under which of the following conditions will this be considered an Initial Value Problem?
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Step-by-Step Analysis
The question asks about when a second-order ODE is considered an Initial Value Problem (IVP).
First, recall the typical criteria for an IVP for a second-order equation: you must be given the value of the function and the value of its first derivative at a specific initial point x = x0. In other words, you need two initial conditions of the form y(x0) = y0 and y'(x0) = v0.
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Similar Questions
Solve the initial value problem: ย ย ย ย ย ย 25 ๐ฅ โณ + 20 ๐ฅ โฒ + 229 ๐ฅ = 0 , ๐ฅ ( 0 ) = 2 , ๐ฅ โฒ ( 0 ) = โ 2.
Let ๐ฆ ( ๐ฅ ) be a solution to the initial value problem: ๐ ๐ฆ ๐ ๐ฅ โ ( 9 ๐ฅ + 8 ) ๐ฆ 2 = 0 , ๐ฆ ( โ 1 ) = โ 2. What is the value of ๐ฆ ( โ 2 ) ? Hints: Use the method of separation of variables to solve the initial value problem. โซ ๐ฅ ๐ ๐ ๐ฅ = ๐ฅ ๐ + 1 ๐ + 1 + ๐ถ .
Let [math: y] be a twice differentiable function in [math: x] such that [math: yโณ+5yโฒ+6y=0]yโโ+5yโ+6y=0, [math: y(0)=1] and [math: yโฒ(0)=2]yโ(0)=2. Compute [math: y(1)]. (Correct the answer to 2 decimal places.)
Let [math: y] be a twice differentiable function in [math: x] such that [math: yโณ=2yโฒโ2y]yโโ=2yโ-2y, [math: y(0)=1] and [math: yโฒ(0)=3]yโ(0)=3. Compute [math: y(1)]. (Correct the answer to 2 decimal places.)
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