What value would the variable x have after the following line of code: x = 1 5 Note - The values of x shown below are logical 0 (False) and logical 1 (True)

Question

What value would the variable x have after the following line of code: x = 1 < 8 + ~10 > 5

Note - The values of x shown below are logical 0 (False) and logical 1 (True)

BlackTom AI · Accepted Answer

The problem presents an expression x = 1 < 8 + ~10 > 5 and asks what value x would take. First, we need to understand operator precedence and how the expression would be parsed in a C-like context. The bitwise NOT operator ~ has higher precedence than addition, so we evaluate ~10 first. In two's complement representation, ~10 equals -11. Next, we compute the addition: 8 + (-11) = -3. Now the expression becomes x = 1 < -3 > 5. In C-like languages, relational operators do not chain; the expression is parsed as (1 < -3) > 5. Evaluating 1 < -3 yields 0 (false). So the left side is 0. The next comparison is 0 > 5, which is also false, yielding 0 again. Therefore, x gets assigned the value 0. Regarding the options: there are no answer choices provided to evaluate, so we cannot comment on which option corresponds to x = 0. However, based on the standard interpretation of operator precedence and the typical semantics of < and > in such languages, the result x = 0 is consistent with the step-by-step evaluation described above. If you intended a different language with different chaining semantics for relational operators, the result could differ, but in mainstream C-like syntax the conclusion x = 0 holds true.

ENGR 1181.01 AU2025 (4684) Practice Quiz 3

What value would the variable x have after the following line of code: x = 1 < 8 + ~10 > 5 Note - The values of x shown below are logical 0 (False) and logical 1 (True)

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ENGR 1181.01 AU2025 (4684) Practice Quiz 3

What value would the variable x have after the following line of code: x = 1 < 8 + ~10 > 5 Note - The values of x shown below are logical 0 (False) and logical 1 (True)

View Explanation

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