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BU-STAT-2103-750-49509-202503 Test 2

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Previous studies find that TUJ statistics students get 7 hours of sleep per night, on average. A survey of 25 TUJ statistics students generated a mean of 7.4 hours with a standard deviation of 1.9 hours. At a level of significance of 10%, can it be concluded that TUJ statistics students get more than 7 hours of sleep per night, on average?   USE THE TABLES POSTED IN CANVAS TO SOLVE THIS PROBLEM.   Round to THREE DECIMAL PLACES. Example: If C.V. = +9.123, enter 9.123 as your answer. If C.V. = -9.123, enter -9.123 as your answer. If C.V. = +/-9.123, enter +/-9.123 as your answer. Determine the critical value(s), C.V. = [Fill in the blank],   If H1: μ≠19\mu\ne19,  enter NET19 as your answer without any space between terms (NET: Not Equal To). If H1: μ < 19, enter <19 as your answer without any space between terms. If H1: μ > 19, enter >19 as your answer without any space between terms. State the alternative hypothesis: [Fill in the blank],7" readonly="readonly" aria-label="Fill in the blank, read surrounding text">   Round to TWO DECIMAL PLACES. Example: If test statistic = +0.12, then enter 0.12 as your answer. If test statistic = -0.12, then enter -0.12 as your answer. Compute the test statistic: [Fill in the blank],   If your decision is “Reject the null hypothesis”, enter R as your answer If your decision is “Do Not Reject the null hypothesis”, enter DNR as your answer Make the decision to reject or not reject the null hypothesis: [Fill in the blank],

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To approach this problem, I’ll walk through the key steps of a one-sample t-test for the mean with H0: μ = 7 (based on the problem statement that TUJ statistics students sleep about 7 hours on average) versus H1: μ > 7, at a significance level of 0.10. The sample has n = 25, x̄ = 7.4, s = 1.9. First, calculate the test statistic. The formula is t = (x̄ − μ0) / (s/√n). - Numerator: x̄ − μ0 = 7.4 − 7 = 0.4. - Denominator: s/√n = 1.9 / √25 = 1.9 / 5 = 0.38. So t = 0.4 / 0.38 ≈ 1.0526, which rounds to 1.05 to two decimals. This is the test statistic you should enter for ......Login to view full explanation

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