How many moles of HCl are there in 10 mL of a solution with a concentration of 0.5 mol/L?

Question

BlackTom AI · Accepted Answer

First, restate the problem in my own words: You have a solution with a concentration of 0.5 M (0.5 moles per liter) and a volume of 10 mL, and you want to know how many moles of HCl are present.

Option a: 0.005 mol. To obtain moles from concentration and volume, use n = C × V. Here C = 0.5 mol/L and V = 10 mL = 0.01 L. Multiplying gives n = 0.5 × 0.01 = 0.005 mol. This matches the calculated amount, so this option reflects the correct calculation in SI units.

Option b: 5 mol. This would require a much larger amount of solution or a much higher concentration. For example, 0.5 mol/L × 10 L would give 5 mol. Since the volume here is only 0.01 L, obtaining 5 mol would be incorrect, indicating a mismatch between volume and concentration.

Option c: 0.5 mol. This would correspond to having 1 L of a 0.5 M solution, since 0.5 mol/L × 1 L = 0.5 mol. The given volume is 0.01 L, not 1 L, so this value arises from an incorrect volume assumption.

Option d: 0.05 mol. This would come from 0.5 mol/L × 0.1 L = 0.05 mol. The calculation would be valid if the volume were 100 mL (0.1 L), but the problem states 10 mL, so this is a volume-area misapplication.

In summary, the key steps are to convert the volume to liters and apply n = C × V. The only choice that aligns with 0.5 mol/L × 0.01 L is 0.005 mol, while the other options reflect common unit or arithmetic slips stemming from incorrect volume assumptions or misapplied formulas.

BPS2022 S2 2025 PA Pre-lab quiz for experiment 3b (2025)

How many moles of HCl are there in 10 mL of a solution with a concentration of 0.5 mol/L?

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