In cattle, the gene for polled (hornless) condition is dominant (P) to the gene for horned (p). A homozygous polled bull is mated with a horned cow.

Complete the Punnett square for this cross and answer the following:

What percentage of their offspring will be polled?

Punnett Square:

P P
p
p

Question

In cattle, the gene for polled (hornless) condition is dominant (P) to the gene for horned (p). A homozygous polled bull is mated with a horned cow.

Complete the Punnett square for this cross and answer the following:

What percentage of their offspring will be polled?

Punnett Square:

P  	P  
p		
p

BlackTom AI · Accepted Answer

Consider the genetics given: the polled allele (P) is dominant to the horned allele (p). A homozygous polled bull has the genotype PP, while a horned cow has the genotype pp.

When we cross PP (bull) with pp (cow), every gamete from the father carries P and every gamete from the mother carries p. Filling out the Punnett square, all offspring receive one P allele from the father and one p allele from the mother, yielding the genotype Pp for every offspring.

Since P is dominant over p, all Pp individuals will display the polled phenotype. Therefore, every offspring in this cross will be polled.

If there were any other possible offspring genotypes or phenotypes, they would require a different parental combination (for example, PP x Pp or pp x Pp), but in this cross the maternal genotype is pp and the paternal genotype is PP, so the result is uniformly Pp and polled.

In summary, given the parental genotypes, the cross produces only Pp offspring with the polled phenotype for 100% of the progeny.

AGRI10051_2025_SM2 Revision Questions Weeks 1-4 UNMARKED

In cattle, the gene for polled (hornless) condition is dominant (P) to the gene for horned (p). A homozygous polled bull is mated with a horned cow. Complete the Punnett square for this cross and answer the following: What percentage of their offspring will be polled? Punnett Square: P P p p

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