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Question at position 13 [1−12][[4−10][23]+[1001−11]]=\begin{bmatrix} 1 & -1 & 2 \\ \end{bmatrix} \left[ \begin{bmatrix} 4 \\ -1\\ 0 \end{bmatrix} \begin{bmatrix} 2 &3 \\ \end{bmatrix} + \begin{bmatrix} 1 & 0 \\ 0 & 1 \\ -1 & 1 \end{bmatrix} \right] =[2−34810]\begin{bmatrix} 2 & -3 \\ 4 & 8 \\ 1 & 0 \end{bmatrix}none of the above[29−3]\begin{bmatrix} 2 & 9 & -3 \\ \end{bmatrix}[5−7]\begin{bmatrix} 5 \\ -7 \end{bmatrix}[912]\begin{bmatrix} 9 & 12 \\ \end{bmatrix}

Options
A.[ 2 − 3 4 8 1 0 ]
B.none of the above
C.[ 2 9 − 3 ]
D.[ 5 − 7 ]
E.[ 9 12 ]
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Step-by-Step Analysis
We begin by clarifying the structure of the question and the given answer options, since this involves matrix and vector multiplication which can be error-prone if dimensions don’t align. Option 1 presents a 3×2 block with entries 2, −3, 4, 8, 1, 0 arranged in two columns. Since the target seems to be a 3×1 column vector judging from the other options, this 3×2 arrangement cannot be the correct form for a single column result, so this option is inconsistent with the expected output format. Option 2 is “none of the above.” To evaluate this, we need to determine what the actual result should be; if the computed result is any of the listed column vectors, then “none of the above” would be incor......Login to view full explanation

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