A proton travels perpendicular to a magnetic field of strength 0.400 T at a speed of 1.50 × 10⁶ m/s. What is the magnetic force on it? (q = 1.60 × 10⁻¹⁹ C)

Question

BlackTom AI · Accepted Answer

We are asked to find the magnetic force on a proton moving perpendicular to a magnetic field. The magnetic force on a charge is F = q v B when v is perpendicular to B.

Option a: 9.60 × 10⁻¹⁴ N
- Compute F = (1.60 × 10⁻¹⁹ C) × (1.50 × 10⁶ m/s) × (0.400 T).
- First multiply velocity and field: 1.50 × 10⁶ × 0.400 = 6.0 × 10⁵.
- Then multiply by the charge: (1.60 × 10⁻¹⁹) × (6.0 × 10⁵) = 9.6 × 10⁻¹⁴ N.
- This matches the value 9.60 × 10⁻¹⁴ N.

Option b: 8.00 × 10⁻¹⁴ N
- If you tried to get this, you would have to miscalculate the product of q, v, and B, such as using 1.60 × 10⁻¹⁹ × 5.0 × 10⁵ or misplacing a decimal. The correct product with the given numbers does not yield 8.00 × 10⁻¹⁴ N.

Option c: 7.50 × 10⁻¹⁴ N
- This would arise from another incorrect combination of the factors, perhaps using a slightly different intermediate product (e.g., 1.50 × 10⁶ × 0.400 = 6.0 × 10⁵, but then misapplying the exponent when multiplying by 1.60 × 10⁻¹⁹). The exponent and leading coefficient do not align with the precise calculation.

Option d: 6.00 × 10⁻¹⁴ N

- This value is smaller than the exact result by a factor of 1.6, which could come from mistakenly using q = 1.0 × 10⁻¹⁹ C or dropping a factor of 1.6 in the multiplication. The proton’s charge is 1.60 × 10⁻¹⁹ C, so omitting the 1.60 would yield a smaller result that does not match the given numbers.

Overall, the correct computation uses F = q v B with the provided values, yielding 9.60 × 10⁻¹⁴ N. The other options arise from common arithmetic slips or misapplication of the factors, rather than from the correct formula and inputs.

SPH4U - Physics 12 (2025-26) - A

A proton travels perpendicular to a magnetic field of strength 0.400 T at a speed of 1.50 × 10⁶ m/s. What is the magnetic force on it? (q = 1.60 × 10⁻¹⁹ C)

View Explanation

Log in for full answers

Similar Questions

What happens to the velocity of a charged particle moving at any angle with respect to the magnetic field?

What happens to the velocity of a charged particle moving in perpendicular direction to the magnetic field?

What happens to a charged particle moving in a magnetic field?

A positive charge moving with a constant velocity V enters a region of a uniform magnetic field directed out of the page. What is the direction of the magnetic force on the charge?

A positive charge moving with a constant velocity V enters a uniform magnetic field directed to the top of the page. What is the direction of the magnetic force on the charge?

A negative charge moving with a constant velocity V enters a uniform magnetic field directed out of the page. What is the direction of the Lorentz force on the charge?

A straight wire carries an electric current to the right. The current is within a uniform magnetic field directed into the page. What is the direction of the Lorentz force?

More Practical Tools for Students Powered by AI Study Helper

Homework AI Solver

Stylized AI Paper Writer

Plagiarism Checker Assistant

Citation AI Academic Writing Tool

In-Class Translation Assistant

AI Note Generator

AI Quiz Answers

Past Exam Questions from University Test Bank

Smart Practice Assistant

Adaptive Practice

Making Your Study Simpler