Questions
CMPSC 132 Spring 2025 Module 5 Checkpoint
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In the LinkedList class implemented in Module 5, we want to add the property method getMax that returns the node with the maximum value stored in the list. You can assume nodes contain unique numerical values. For example, if the Linked List is 1->22->3->4->5, then a call to this method should return Node(22). Linked list has a reference to head and tail nodes @property def getMax(self): """ >>> x=LinkedList() >>> x.add(5) >>> x.add(6) >>> x.add(9) >>> x.append(5559) >>> x.append(55) >>> x.getMax Node(5559) """ if [ Select ] not self.isEmpty() self self.head.next self.isEmpty() : max_node = [ Select ] self.head self.head.next.value self.tail.next self.head.next current = [ Select ] self.tail.next self.tail self.head.next self while [ Select ] current.next is not None current is not None self.head is not None max_node is not None : if [ Select ] current.next.value current.next current current.value > [ Select ] max_node.next max_node max_node.value self.head.value : max_node = current current = [ Select ] current.next.next current.next.value current.next current return [ Select ] max_node current current.next max_node.next
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Step-by-Step Analysis
Let's walk through the intended getMax method piece by piece, evaluating each option to see where it fits in a correctly implemented traversal.
Option: not self.isEmpty()
Reasoning: The method should first guard against an empty list. Using not self.isEmpty() ensures we only proceed if the list has at least one node. This check prevents accessing head on an empty structure and is the standard precondition for max operations on a linked list.
Option: self.head
Reasoning: We need to ......Login to view full explanationLog in for full answers
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