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Question29 Consider the functions [math] and [math]. Use the Wronskian to decide whether these functions are linearly independent on the interval [math]. Which of the following gives the correct answer and appropriate justification for it? Select one alternative: [math] has nonzero determinant for every value of [math], so the functions are linearly independent. [math]has determinant equal to zero for every value of [math], so the functions are linearly independent. [math]has determinant equal to zero for every value of [math], so the functions are linearly dependent. [math]has nonzero determinant for every value of [math], so the functions are linearly dependent. ResetMaximum marks: 1 Flag question undefined

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A. [e2t3e2t2e2t6e2t]   has nonzero determinant for every value of t , so the functions are linearly independent.
B. [e2t3e2t2e2t6e2t] has determinant equal to zero for every value of t , so the functions are linearly independent.
C. [e2t3e2t2e2t6e2t] has determinant equal to zero for every value of t , so the functions are linearly dependent.
D. [e2t3e2t2e2t6e2t] has nonzero determinant for every value of t , so the functions are linearly dependent.
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We start by restating the problem and the available choices to ensure clarity about what is being evaluated. Question: Use the Wronskian to decide whether the given pair of functions are linearly independent on the interval [ ] and identify which option provides the correct justification. Answer options: 1) [e2t3e2t2e2t6e2t] has nonzero determinant for every value of t, so the functions are linearly independent. 2) [e2t3e2t2e2t6e2t] has determinant equal to zero for every value of t, so the functions are linearly independent. 3) [e2t3e2t2e2t6e2t] has determinant equal to zero for every value of t, so the functions are linearly dependent. 4) [e2t3e2t2e2t6e2t] has nonzero determinant for every value of t, so the functions are linearly dependent. Option-by-option analysis: Option 1: Nonzero determinant for every value of t implies the Wronskian never vanishes on the interval. In many texts this is presented as a ......Login to view full explanation

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