Questions
MATH-112-301-001 Unproctored Midcourse 1 Practice Exam 2
Single choice
Determine which graph satisfies all of these properties: ๐ ( 0 ) = 2 ,ย lim ๐ฅ โถ 0 โ ๐ ( ๐ฅ ) = 4 ,ย lim ๐ฅ โถ 0 + ๐ ( ๐ฅ ) = 2 , lim ๐ฅ โถ โ โ ๐ ( ๐ฅ ) = โ โ ,ย lim ๐ฅ โถ 4 โ ๐ ( ๐ฅ ) = โ โ , lim ๐ฅ โถ 4 + ๐ ( ๐ฅ ) = โ ,ย lim ๐ฅ โถ โ ๐ ( ๐ฅ ) = 3
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Step-by-Step Analysis
The provided data for the problem includes a question stem and a set of properties, but there are no answer options given to evaluate against the graph. Without labeled options to compare, we cannot identify which graph satisfies all the listed conditions.
What we do have to work with is the list of required properties for f:
- f(0) = 2
- limit as x approaches 0 from the left of f(x) = 4
- limit as x approaches 0 from the right of f(x) = 2
- limit as x approaches -infinity of f(x) = -infinity
- limit as x approach......Login to view full explanationLog in for full answers
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Consider this graph of the functionย ๐ ( ๐ฅ ) . Which of the following statements are true and which are false?ย lim ๐ฅ โ 3 โ ๐ ( ๐ฅ ) = lim ๐ฅ โ 3 + ๐ ( ๐ฅ ) [ Select ] False True lim ๐ฅ โ 1 ๐ ( ๐ฅ ) = ๐ ( 1 ) ย ย [ Select ] True False ๐ ( ๐ฅ ) ย has a vertical asymptote at ๐ฅ = 4 . [ Select ] False True ๐ ( ๐ฅ ) ย has a vertical asymptote at ๐ฅ = 6 ย . [ Select ] False True lim ๐ฅ โ 4 โ ๐ ( ๐ฅ ) = lim ๐ฅ โ 4 + ๐ ( ๐ฅ ) [ Select ] False True lim ๐ฅ โ 4 ๐ ( ๐ฅ ) = โ [ Select ] True False lim ๐ฅ โ 6 ๐ ( ๐ฅ ) = โ [ Select ] False True The limit lim ๐ฅ โ 4 ๐ ( ๐ฅ ) exists, but lim ๐ฅ โ 6 ๐ ( ๐ฅ ) ย does not exist. [ Select ] False True
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