An object 20 cm from a convex lens of focal length 4 cm will produce an image Blank 1 Question 3[select: , 0.2 cm, 4 cm, 80 cm, 5 cm] from the lens.

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To start, identify the lens setup: a convex lens with focal length f = +4 cm and an object placed at u = -20 cm (taking left of the lens as negative in the standard sign convention). The thin lens equation is 1/f = 1/v - 1/u, which can be rearranged to 1/v = 1/f + 1/u.

Plugging in the values: 1/v = 1/4 + 1/(-20) = 0.25 - 0.05 = 0.20. Solving for v gives v = 1/0.20 = 5 cm.

The positive sign of v indicates the image is formed on the opposite side of the lens (to the right), i.e., a real image on the image side. The magnification is m = v/u = 5/(-20) = -0.25, which tells us the image is inverted and reduced in size compared to the object.

Therefore, the image distance from the lens is 5 cm to the right of the lens. This is consistent with a real, inverted, diminished image formed by a convex lens when the object is placed beyond the focal length (outside f = 4 cm).

MUF0122 Physics Unit 2 - Semester 2, 2025 3.23 Lens formula

An object 20 cm from a convex lens of focal length 4 cm will produce an image Blank 1 Question 3[select: , 0.2 cm, 4 cm, 80 cm, 5 cm] from the lens.

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