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Question at position 8 Using the nomenclature above, which partial diploid strain will produce β-galactosidase constitutively, and induce expression of permease and transacetylase (A) ?I = Lac repressor genep = the promotero = the operatorZ = the lacZ geneY= the lacY geneA = the lac A geneIsp+ocZ+Y-A-/I-p+o+Z-Y+A+I-p+o+Z+Y-A-/I-p+o+Z-Y+A+I+p-o+Z+Y-A-/I-p+o+Z-Y+A+I+p+ocZ+Y-A-/I+p-o+Z-Y+A+I+p+ocZ+Y-A-/I-p+o+Z-Y+A+Clear my selection
Options
A.Isp+ocZ+Y-A-/I-p+o+Z-Y+A+
B.I-p+o+Z+Y-A-/I-p+o+Z-Y+A+
C.I+p-o+Z+Y-A-/I-p+o+Z-Y+A+
D.I+p+ocZ+Y-A-/I+p-o+Z-Y+A+
E.I+p+ocZ+Y-A-/I-p+o+Z-Y+A+
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Step-by-Step Analysis
We start by restating the problem to ensure understanding: We are asked, for a partial diploid Lac operon arrangement, which genotype would yield constitutive production of β-galactosidase (Z) while still allowing the permease (Y) and transacetylase (A) to be inducible.
Option 1: I+p+ocZ+Y-A-/I-p+o+Z-Y+A+
- Here, the left plasmid copy contains I+ (no repressor), oc (constitutive operator mutation), Z+ (functional β-galactosidase gene on, constitutive), Y- (permease gene off), A- (transacetylase gene off). The right copy has I- (repressor present), p+ (promoter active), o+ (operator functional), Z- (no β-galactosidase expression), Y+ (permease on), A+ (transacetylase on).
- Implication: Z is constitutive on the left, but Z on the right is repressed,......Login to view full explanationLog in for full answers
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Similar Questions
When glucose is present, and lactose is absent in the bacteria cell’s environment, which of the following is INCORRECT with respect to the lac operon?
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