Write the IUPAC name of the following alkene?

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BlackTom AI · Accepted Answer

No answer options were provided to analyze individually, so I will explain the reasoning steps you would use to name the given alkene and then relate them to the provided answer.

First, identify the longest carbon chain that contains the carbon–carbon double bond. In this structure, the longest chain that includes the double bond is a six-carbon chain, giving the base name hexene.

Next, assign the position of the double bond. The numbering of the main chain should give the lowest possible locant to the double bond. In this molecule, the double bond is placed between C-2 and C-3 when numbered in the direction shown, so the base name becomes hex-2-ene.

Then, locate and name substituents on the main chain. There is a methyl group and an ethyl group attached to the same carbon (C-4) of the main chain. When multiple substituents are present at the same carbon, they are named as substituents with their respective carbon numbers.

Now assign the correct set of locants for the substituents. Both the methyl and the ethyl groups appear on C-4, giving 4-methyl and 4-ethyl as substituents.

Combine the substituents in alphabetical order (ethyl comes before methyl) along with the base name hex-2-ene. Since both substituents share the same carbon, you still list each substituent with its own number: 4-ethyl-4-methyl. The final IUPAC name is therefore 4-ethyl-4-methylhex-2-ene.

Why other potential names would be incorrect:
- If you tried to number the main chain from the opposite end, the double bond would be assigned the locant 4, which is less favorable than 2 for the double bond, so that numbering is rejected by the rule for lowest set of locants.
- If you omitted the locant for the double bond or miscounted the substituent positions, you would produce an incorrect base name (e.g., hex-1-ene instead of hex-2-ene) or wrong substituent positions (e.g., 3-ethyl-3-methyl or similar), which does not match the actual structure.
- If the substituents were named in reverse order or without alphabetical arrangement, the name would not conform to IUPAC conventions, though it would convey the same structure.

In summary, following the IUPAC rules for longest chain selection, double bond locant assignment, substituent identification, and proper ordering yields 4-ethyl-4-methylhex-2-ene as the correct name for the given alkene.

My LMS Subjects Quiz 1

Write the IUPAC name of the following alkene?

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