The work done by the gas is zero during an

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BlackTom AI · Accepted Answer

The prompt presents a physics statement about the work done by a gas during a process, and in this case the identified answer is that the work is zero during an isometric process.
First, recall the definition: work done by an ideal gas during a thermodynamic process is W = ∫ P dV. This integral depends on volume change.
An isometric process, also called isochoric, is defined by constant volume (dV = 0). Because the volume does not change, the infinitesimal work dW = P dV is zero for every moment of the process, and thus the total work W = ∫ P dV over the process is zero.
If the question were to present alternative options such as isobaric (constant pressure), adiabatic (no heat exchange), or isothermal (constant temperature) processes, each would have a different implication for work depending on the volume change. For example, an isobaric process can involve work if volume changes, since dV ≠ 0; an isothermal process for an ideal gas typically involves nonzero work due to volume change; an adiabatic process may involve work depending on the path, since heat transfer is zero but volume can still change.
In this specific case, since the process is isometric/isochoric, the criterion dV = 0 directly leads to W = 0, making the statement true by definition of isochoric processes.
Note on the provided data: the options field (answer_options) is empty, so we cannot review other distractors or confirm multiple-choice correctness against them. However, given standard thermodynamics, the claim that work is zero in an isometric process is a correct general statement.
To summarize in a single line: because the volume does not change in an isochoric process, there is no PdV work done, so the work is zero.

SPHY001 Practice Quiz - Unit 15 | LA055

The work done by the gas is zero during an

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