F- is a
[ Select ]
cation
anion
and is formed due to the
[ Select ]
gain
loss
of electron(s)

Question

F- is a 
[ Select ]
cation
anion
 and is formed due to the 
[ Select ]
gain
loss
 of electron(s)

BlackTom AI · Accepted Answer

The question presents a fill-in-the-blank style with two dropdowns to complete: 'F- is a [Select]cation and is formed due to the [Select] gain [Select] loss of electron(s)'.

First, consider the identity of F- (fluoride). The minus sign indicates a negative charge, which means it is an anion, not a cation. Therefore, the correct first dropdown is 'anion'.

Next, determine how F- is formed. Fluorine gains electrons to achieve a more stable electron configuration, giving it a negative charge. This means the process involves the gain of electrons, not the loss. Therefore, the correct second dropdown is 'gain' for the action that creates F-.

To anticipate common misconceptions: choosing 'cation' would imply a positively charged species, which contradicts the negative charge of F-. Choosing 'loss' would describe removal of electrons, which would typically produce a positively charged ion (or a less negative species), not the negatively charged fluoride ion. Likewise, mixing up 'gain' and 'loss' reverses the physical process by which the ion forms.

In summary, completing the blanks with the logically correct terms yields: 'F- is an anion and is formed due to the gain of electron(s)'. This aligns with fundamental concepts of ionic charge, electron transfer, and the formation of anions through electron gain.

F- is a [ Select ] cation anion and is formed due to the [ Select ] gain loss of electron(s)

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