Select the response which presents the three elements below in order of increasing first ionisation potential (IE1).

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To determine the correct order, we need the first ionization energies (IE1) of Te, I, and Br. 
Option a: Br, I, Te — this sequence implies IE1(Br) < IE1(I) < IE1(Te). In reality, Br has a higher IE1 than I, and I is higher than Te, so this order is incorrect. 
Option b: Br, Te, I — this suggests IE1(Br) < IE1(Te) < IE1(I). Since Br’s IE1 is the largest among the three, this cannot be right. 
Option c: I, Br, Te — this presents IE1(I) < IE1(Br) < IE1(Te). But Br’s IE1 is greater than I’s, and Te’s IE1 is the smallest, so this is not accurate. 
Option d: I, Te, Br — this implies IE1(I) < IE1(Te) < IE1(Br). However Te’s IE1 is smaller than I’s, not larger, so this ordering is incorrect. 
Option e: Te, Br, I — this sequence indicates IE1(Te) < IE1(Br) < IE1(I). While Te is the smallest, Br is not the middle here, since I’s IE1 is still greater than Br’s, so this arrangement is false. 
Option f: Te, I, Br — this order means IE1(Te) < IE1(I) < IE1(Br). This matches the known values: Te has the smallest IE1, I is intermediate, and Br has the largest. 
Given the actual IE1 values, the increasing order is Te < I < Br, which corresponds to option f. 
In summary, the correct progression follows the trend across the periodic table where ionization energy generally increases across a period and down a group affects the exact values, but for these three elements Te (a metalloid in period 5), I (halogen in period 5), and Br (halogen in period 4) the smallest to largest IE1 is Te, then I, then Br.}

CHM1051 MUM S2 2025 CHM1051 Practice Exam 1

Select the response which presents the three elements below in order of increasing first ionisation potential (IE1).

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