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Questions
PHR 2410 SP2025 (36478) PRACTICE (Expected): Case Study #2
Multiple choice
Part II Reflect on the answer you chose for Question 1. Explain the rationale behind your selected answer. In your response, discuss how the drug action of an INCS mediates its therapeutic effect and identify 1-2 characteristics that distinguish it from antihistamines. Before we practice a response, what resource(s) should you consult to help you develop your answer?
Options
A.The drug facts label for either an antihistamine or an INCS
B.The Module 3 faculty lectures about antihistamines and INCS
C.Scholarly research articles that discuss OTC allergy medications
View Explanation
Standard Answer
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Approach Analysis
When determining what resources to consult to develop a well-supported answer, start by identifying sources that provide authoritative, course-focused information.
Option 1: The drug facts label for either an antihistamine or an INCS. This is a primary, regulated source that gives specific, evidence-based details on drug action, indications, dosing, and safety. It is a strong foundat......Login to view full explanationLog in for full answers
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Question text The students below each construct a sinusoidal function based on a shared scenario involving water level fluctuations.Match each student’s reasoning to the explanation that best fits their thinking. Scenario:The depth of water , in metres, at a canal dock fluctuates due to the system of canal locks lowering and raising the water for container ships. The water varies sinusoidally from a minimum of 1.5 m to a maximum of 4.5 m. The depth reaches its minimum at 5:00 AM, and one full cycle of the water level is completed every 4 hours. The horizontal axis represents time , in hours, where corresponds to midnight. Student 1:I was asked to find the water depth at 3 AM.The equation I created was Since the minimum occurs at 5:00 AM, I shifted the function by 5.Using this function, I found the depth at 3 AM was 1.5 m.Answer 1 Question 22[select: , All parameters are correct. Therefore, the initial evaluation is correct, and the correct depth at 3 AM is 1.5 m. , All parameters are correct except the phase shift: there should be a phase shift of -5. Therefore, the initial evaluation is incorrect; using the new equation, the correct depth at 3 AM is 4.5 m. , All parameters are correct except the k-value: the k-value should be pi/4. The initial evaluation is still correct; the depth at 3 AM is 1.5 m.] Student 2:I was asked to find the water depth at 6 AM.The equation I created was I chose sine because the water starts rising after its lowest point.Using my equation, I found the depth at 6 AM was 3 m.Answer 2 Question 22[select: , All parameters are correct except for the amplitude, which should be negative. The initial evaluation is still correct; the depth at 6 AM is 3 m., All parameters are except the phase shift: there should be a phase shift of -5. Therefore, the initial evaluation is incorrect; using the new equation, the correct depth at 6 AM is 4.1 m., All parameters are correct except the k-value; the k-value should be pi/2. The initial evaluation is still correct; the depth at 6 AM is 3 m. ] Student 3:I was asked to find the water depth at 1 PM.The equation I created was Since the minimum occurs at 5:00 AM, I used a cosine function with a shift to match the point.I found the depth at 1 PM to be 4.5 m.Answer 3 Question 22[select: , All parameters are correct except the k-value; the correct k-value is pi/4. The initial evaluation is still correct; the depth at 1 PM is 4.5 m., All parameters are correct except for the phase shift; there should be a phase shift of -3. Therefore, the initial evaluation is incorrect; using the new equation, the correct depth at 1 PM is 1.5 m.. , All parameters are correct and the student’s evaluation of the depth was correct; the depth at 1 PM is 4.5 m.]
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