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Question at position 1 ∫x+1(x2+2x)2dx=\int\frac{x+1}{\left(x^2+2x\right)^{^2}}dx=(x2+2x)36+C\frac{\left(x^2+2x\right)^{^3}}{6}+C(x2+2x)33+C\frac{\left(x^2+2x\right)^{^3}}{3}+C−12(x2+2x)−1+C-\frac{1}{2}\left(x^2+2x\right)^{^{-1}}+C(x2+2x)32+C\frac{\left(x^2+2x\right)^{^3}}{2}+C−(x2+2x)−1+C-\left(x^2+2x\right)^{^{-1}}+C

Options
A.( 𝑥 2 + 2 𝑥 ) 3 6 + 𝐶
B.( 𝑥 2 + 2 𝑥 ) 3 3 + 𝐶
C.− 1 2 ( 𝑥 2 + 2 𝑥 ) − 1 + 𝐶
D.( 𝑥 2 + 2 𝑥 ) 3 2 + 𝐶
E.− ( 𝑥 2 + 2 𝑥 ) − 1 + 𝐶
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Step-by-Step Analysis
We are evaluating multiple choices for the antiderivative of a function that appears to be (x+1)(x^2+2x)^2, based on the structure of the options. Option 1: ((x^2+2x)^3)/6 + C. If we differentiate this, we get (1/6)*3*(x^2+2x)^2*(2x+2) = (x^2+2x)^2*(x+1). This exac......Login to view full explanation

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