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Integration by parts [math: ∫f′(x)g(x)dx=f(x)g(x)−∫f(x)g′(x)dx]\int f'(x) g(x) \, dx = f(x) g(x) - \int f(x) g'(x) \, dx is the partial integral counterpart to which of the following rules?
Options
A.a. Product Rule: [math: (f(x)g(x))′=f′(x)g(x)+f(x)g′(x)](f(x)g(x))' = f'(x)g(x) + f(x)g'(x)
B.b. Addition Rule: [math: (f(x)+g(x))′=f′(x)+g′(x)](f(x) + g(x))' = f'(x) + g'(x)
C.c. Quotient Rule:[math: (f(x)g(x))′=f′(x)g(x)−f(x)g′(x)[g(x)]2] \left(\frac{f(x)}{g(x)}\right)' = \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2}
D.d. Chain Rule: [math: (f(g(x)))′=f′(g(x))⋅g′(x)](f(g(x)))' = f'(g(x)) \cdot g'(x)
E.e. Power Rule: [math: (f(x)g(x))′=f(x)g(x)(g′(x)ln(f(x))+g(x)f′(x)f(x))](f(x)^{g(x)})' = f(x)^{g(x)} \left( g'(x) \ln(f(x)) + \frac{g(x) f'(x)}{f(x)} \right)
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The question asks: Integration by parts, expressed as ∫ f'(x) g(x) dx = f(x) g(x) − ∫ f(x) g'(x) dx, is the partial integral counterpart to which rule?
Option a: Product Rule: (f(x)g(x))' = f'(x)g(x) + f(x)g'(x). This corresponds to how the derivative of a product expands, and integration by parts is essentially derived from rearranging this product rule. Thus, t......Login to view full explanationLog in for full answers
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