What is the purpose of using an integrating factor when solving a first-order linear differential equation?

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BlackTom AI · Accepted Answer

When approaching a first-order linear differential equation of the form y' + p(x) y = q(x), several ideas might come to mind about what a integrating factor accomplishes. 
Option a: 'To reduce the order of the differential equation.' This is not the goal of the integrating factor. The equation is already first order; the integrating factor does not change its order. Instead, it rephrases the equation so that the left-hand side becomes the derivative of a product, not a reduction in order. 
Option b: 'To transform the equation into a simple integral.' This is the essence of the integrating factor method. By multiplying through by μ(x) = exp(∫ p(x) dx), the equation becomes d/dx [μ(x) y] = μ(x) q(x). Integrating both sides with respect to x yields μ(x) y = ∫ μ(x) q(x) dx + C, which is a straightforward integral equation for y. This option captures the primary mechanism and payoff of the method. 
Option c: 'To trick the easily tricked into believing that something incredibly deep is happening while in reality nothing of essence changes :)' This is a playful but incorrect characterization. The integrating factor reveals a real underlying structure by converting to an exact-like form; it is a legitimate and useful transformation, not a trick. 
Option d: 'To transform the equation into an equation that is most easily solved by separation of variables.' While separation of variables can solve certain equations, the integrating factor method does not generally produce a separable form. The transformed equation is of the form (μ y)' = μ q, which is integrated with respect to x rather than separated into y and x on opposite sides. In short, the primary purpose is not to enable separation of variables, but to linearize the left-hand side into a derivative of a product. 
Thus, among the given options, the statement that best describes the purpose of using an integrating factor is that it transforms the equation into a simple integral via (μ y)' = μ q, leading to μ(x) y = ∫ μ(x) q(x) dx + C.

MTH1030 -1035 - S1 2025 MTH1030/35 Week 11 lesson quiz: Differential equations

What is the purpose of using an integrating factor when solving a first-order linear differential equation?

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