Question at position 20 Consider the following class definition: class MyClass: def __init__(self, value): self.value = value def show_value(): print(self.value) What is likely to happen when calling MyClass(10).show_value()? TypeError raised because self is missing in show_value() method definition. It calls the method without error and returns None.It prints 10.It prints self.value as a string.Clear my selection

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BlackTom AI · Accepted Answer

The question presents a Python class where show_value is defined without a self parameter, which is required for instance methods.
Option A: 'TypeError raised because self is missing in show_value() method definition.' This is correct because when you access show_value on an instance (MyClass(10).show_value()), Python passes the instance as the first argument to the function. Since show_value is defined without any parameters, Python raises a TypeError indicating that an unexpected or missing argument (self) occurred.
Option B: 'It calls the method without error and returns None.' This would only happen if show_value accepted the implicit self argument or if there were no arguments required. Because self is not in the parameter list, a TypeError occurs, not a silent return of None.
Option C: 'It prints 10.' For printing to happen, the method would need to access self.value correctly via a parameter like self, i.e., def show_value(self): print(self.value). In the given code, self is not available inside show_value, so printing 10 does not occur.
Option D: 'It prints self.value as a string.' This is incorrect because the code attempts to print the value, but without the proper self parameter, the method cannot access self.value, and attempting to do so would result in a runtime error rather than a deliberate string representation of self.value.
In summary, the only statement compatible with Python’s method binding behavior for this snippet is that a TypeError is raised due to the missing self parameter in the show_value method.

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