What is the purpose of the following code snippet?

Question

BlackTom AI · Accepted Answer

We start by examining what the code snippet does when a > b, since the question asks about the purpose of the given branch. Option A: Error. This is unlikely because the nested if-else structure is syntactically valid and logically consistent for comparing a, b, and c. The code is designed to choose an ordering based on comparisons; there’s no immediate syntax or runtime error implied by the structure shown. Option B: None of the others. This would be chosen only if every other statement is false. Since we can logically analyze the branches and see a consistent behavior for the case a > b, this blanket choice is not appropriate. Option C: if a > b, print the three numbers a, b, c in ascending order. Looking at the inner branches, when a > b, the code first checks if a > c. If a > c and b > c, it prints a, b, c. That is descending, not ascending. If a > c and b <= c, it prints a, c, b, which is not strictly ascending either. Therefore, this option misstates the resulting order. Option D: if a > b, print the three numbers a, b, c in descending order. This matches the observed behavior in all subcases under a > b: - If a > b and a > c and b > c, it prints a, b, c (which is descending). - If a > b and a > c and b <= c, it prints a, c, b (still in descending order since a is largest and c >= b). - If a > b and a <= c, it prints c, a, b (c is largest, followed by a, then b), which is also descending. Thus, in every path when a > b, the output is the three numbers in descending order. Taking all options together, the only statement consistent with the actual control flow and outputs when a > b is Option D. The other choices either claim an error, claim a behavior that contradicts the observed print order in the branches, or claim a generic blanket statement that does not fit the branch logic.

COMP1117_1A_2025 Quiz

What is the purpose of the following code snippet?

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