题目
题目

BTRY3010/BTRY5010/STSCI2200/STSCI5200 Lecture #26 Pages ( 126 - 129, 134 )

多重下拉选择题

According to ABCD in 3121, the average American spent $16,803 on housing. A suburban community wants to know if their residents spent less than this national average. In a survey of 30 residents, they found that they spent an annual average of $15,800 with a standard deviation of $2,600. (  𝛼 =0.005 ) The hypothesis for this [ Select ] left-tailed two-tailed right-tailed test would be: 𝐻 0 : [ Select ] µ<15800 µ ≠115800 µ>16803 µ=16803 𝐻 𝑎 : [ Select ] µ≠15800 µ>15800 µ<16803 µ=16803 The possible decision rules for this test can be made using P-values or critical values. Using Critical Values, the null hypothesis is rejected if the test statistic is [ Select ] less greater than [ Select ] 2.33 -1.645 -1.96 -2.756 . Using P-values, the [ Select ] alternative hypthesis null hypothesis is rejected if the P-value is [ Select ] greater less than [ Select ] 0.05 0.10 0.01 0.005 . Using the [ Select ] prop.test T.Test chisq.test function in R, if we had the actual data, we would find that the point estimate of the mean amount a suburban community spend on housing is  [ Select ] $16,803 $2,600 $15,800 30 , the test statistic is [ Select ] $2,600 0.005 .0217 -2.11 $15,800 , and the P-value is [ Select ] 3121 0.02166 0.005 -2.11 . Based on this analysis, we will decide to [ Select ] reject fail to reject the [ Select ] null alternative hypothesis.  We [ Select ] have do not have evidence to suggest their residents spent less than this national average. c08.p080.q003    

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思路分析
We start by restating the problem setup and the key numbers involved in this hypothesis test. A suburban sample of 30 households reports a mean annual housing expenditure of $15,800 with a sample standard deviation of $2,600. The national average is $16,803. The test uses α = 0.005. The question asks us to fill in the blanks for a left-tailed test comparing the suburban mean to the national mean. Option by option analysis: 1) The test direction: should be left-tailed. In this scenario we are testing whether the suburban mean is less than the national average, so the alternative is µ < 16803, which makes the test left-tailed. The choice "left-tailed" is correct here. If we had chosen right-tailed or two-tailed, that would misstate the research question by looking for evidence of a mean greater than or not equal to ......Login to view full explanation

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