The histogram below displays the testscores of a class of students. The number of students is:

Question

BlackTom AI · Accepted Answer

To determine how many students there are, we need to add the frequencies shown by each bar in the histogram.

Option  a. 6: The first bar around score 6 contributes a small frequency, roughly 2 students.

Option  b. 18: The next bar around score 8 contributes about 3 students. Adding this helps accumulate totals but is not the final count.

Option  c. 20: The tall bar around score 10–12 contributes a larger frequency, approximately 5–6 students. The bars to the right decrease gradually, contributing several more students across 12–14, 14–16, 16–18, and a small bar near 28.

Option  d. 21: There is a small bar near the high end (around 28) that adds about 1 student, which pushes the total upward by 1 compared with the previous sum.

Now, summing the visible frequencies across all bars, we get a total in the vicinity of twenty (roughly 20–21 students). Since the options present discrete counts, the value that best matches the sum of all bar heights is 20.

If you tally carefully by each bin: 6–8 ≈ 2, 8–10 ≈ 3, 10–12 ≈ 5–6, 12–14 ≈ 4, 14–16 ≈ 3, 16–18 ≈ 2, 18–20 ≈ 1, and the final bin near 28 ≈ 1; adding these gives about 20–21, with 20 being the closest choice among the options.

The histogram below displays the testscores of a class of students. The number of students is:

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