Consider the following hash table, and a hash function of key % 10. How many list items will be compared for the search operations?

HashInsert(newTable, item 25)

HashInsert(newTable, item 54)

HashRemove(newTable, 27)

HashInsert(newTable, item 84)

HashInsert(newTable, item 83)

HashSearch(newTable, 72)

HashSearch(newTable, 77)

HashSearch(newTable, 63)

Question

Consider the following hash table, and a hash function of key % 10. How many list items will be compared for the search operations?

HashInsert(newTable, item 25)

HashInsert(newTable, item 54)

HashRemove(newTable, 27)

HashInsert(newTable, item 84)

HashInsert(newTable, item 83)

HashSearch(newTable, 72)

HashSearch(newTable, 77)

HashSearch(newTable, 63)

BlackTom AI · Accepted Answer

The question presents a hash table using a hash function key % 10 and a sequence of operations, then asks how many list items will be compared for the search operations.

First, restate the setup: with chaining, each key is placed into bucket index key % 10. The inserts are:
- Insert 25 -> bucket 5
- Insert 54 -> bucket 4
- Remove 27 -> not present, so nothing changes
- Insert 84 -> bucket 4 (collides with 54)
- Insert 83 -> bucket 3

Now, analyze the searches:
- Search 72: bucket 72 % 10 = 2. Bucket 2 has not been used by any insert, so it is empty. Searching an empty bucket requires 0 list item comparisons because you immediately know the item cannot be present in that bucket.
- Search 77: bucket 77 % 10 = 7. Bucket 7 is also empty (no item has been placed there), so this search also requires 0 list item comparisons.
- Search 63: bucket 63 % 10 = 3. Bucket 3 currently contains 83 (from the insert of 83). To determine if 63 is in the list, you compare 63 with the first node in the bucket, which holds 83. Since it does not match, you conclude the item is not in the bucket after that single comparison. Therefore, this search requires 1 list item comparison.

Summarizing the per-search comparisons: 0 for searching 72, 0 for searching 77, and 1 for searching 63. If the question intends the counts per search in that order, the sequence would be 0; 0; 1. If it intends the total number of comparisons across all three searches, the total would be 1.

Important note: The provided data includes an "answer" value of '2; 0; 1' but the answer options field is empty. Because the options are missing, we cannot map the numeric results to specific labeled choices. The analysis above is based on standard chaining behavior and the given operations. The discrepancy (2; 0; 1) likely indicates either a misprint in the provided answer or an alternative counting convention, but with the usual hashing and chaining interpretation, the counts per search are 0, 0, and 1 respectively, yielding a total of 1 across all three searches.

CIS-279-OLH-CRN47413 Quiz: Chapter 6

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