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MAT133 F24-W25 W25 Week 10 Preclass Guided Reading

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Tasks: Let's continue taking partial derivatives. Go to Example 11.3 and work through yourself how the three derivatives (with respect to ๐‘ฅ , ๐‘ฆ , and ๐‘ง ) were computed. At the end of Example 11.3 we are also introduced to the definition of the gradient of a function. If ๐‘“ is a function of ๐‘› variables and all the partial derivatives exist, then the gradient of ๐‘“ is defined to be โˆ‡ ๐‘“ ( ๐‘ฅ ) = ( โˆ‚ ๐‘“ โˆ‚ ๐‘ฅ 1 ( ๐‘ฅ ) , โˆ‚ ๐‘“ โˆ‚ ๐‘ฅ 2 ( ๐‘ฅ ) , โ€ฆ , โˆ‚ ๐‘“ โˆ‚ ๐‘ฅ ๐‘› ( ๐‘ฅ ) ) . This video goes over the definition and some facts on notation: Question: Which of the following functions have gradient โˆ‡ ๐‘“ = ( ๐‘ฆ ๐‘’ ๐‘ฅ ๐‘ฆ + ๐‘ฆ , ๐‘ฅ ๐‘’ ๐‘ฅ ๐‘ฆ + ๐‘ฅ ) ?

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The question asks us to identify the gradient of the function f(x, y) = e^{xy} + xy. First, recall that the gradient โˆ‡f at (x, y) is the vector of partial derivatives: (โˆ‚f/โˆ‚x, โˆ‚f/โˆ‚y). Compute the partial derivative with respect to x: the derivative of e^{xy......Login to view full explanation

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