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BIOL 1009 (001-006/050-055) Midterm Exam III

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This question refers to the following mRNA (messenger RNA) sequence (below) and the universal genetic code shown (below).        5' - ACUACCGGCCCCCGG - 3' The first and last amino acids coded for by this mRNA sequence are   

Options
A.serine; glycine.
B.threonine; arginine.
C.arginine; serine.
D.threonine; proline.
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To tackle this question, I’ll break down the mRNA sequence into codons in the 5' to 3' direction and match each codon to its amino acid using the universal genetic code. First, observe the given mRNA sequence: 5' - ACUACCGGCCCCCGG - 3'. The sequence length is 16 nucleotides, which is not a multiple of 3, so the reading frame must be determined by where translation actually starts. In typical questions like this, translation begins at a start codon (AUG) or at the frame that......Login to view full explanation

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