Questions
ECEN-314:200,501 Final Exam- Requires Respondus LockDown Browser
Single choice
Suppose ๐ฅ ( ๐ก ) is periodic with a period of 2, and one period is described by ๐ฅ ( ๐ก ) = ๐ โ ๐ก for โ 1 < ๐ก โค 1 . Which of the following is the correct form of the Fourier series coefficients? Note: The hyperbolic sine function is defined as sinh ( ๐ฅ ) = 1 2 ( ๐ ๐ฅ โ ๐ โ ๐ฅ ) .
Options
A.๐
๐
=
๐
โ
1
+
๐
๐
๐
โ
๐
1
โ
๐
๐
๐
2
+
๐
2
๐
๐
B.๐
๐
=
๐
๐
๐
โ
(
1
)
(
โ
1
)
๐
1
+
๐
๐
๐
C.๐
๐
=
๐
๐
๐
โ
(
1
)
๐
๐
๐
๐
2
โ
๐
2
๐
๐
D.๐
๐
=
0
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Step-by-Step Analysis
We start by restating the problem context to frame what we are evaluating. The task is to identify the correct form of the Fourier series coefficients X_k for a periodic function x(t) with period 2, where one period is given by x(t) = e^{-t} for -1 < t โค 1. The hyperbolic sine sinh(x) is defined as (e^{x} - e^{-x})/2, which often appears in compact expressions for certain Fourier coefficients when the function involves exponential decay over a symmetric interval.
Option A: X_k = e^{-1} + j k ฯ โ e^{1} โ j k ฯ^2
This option combines exponential terms evaluated at the period endpoints with a quadratic term in k through ฯ^2. However, a typical Fourier coefficient for a piecewise exponential on a symmetric interval does not introduce a direct combination like e^{-1} โ e^{1} scaled by something, nor does it naturally yield a term proportional to ฯ^2 without additional integration factors. The presence of both e^{-1} and e^{1} in a single linear combination, and ......Login to view full explanationLog in for full answers
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