How does a HED of 0.58 mg/kg/d compare to BaP intake from food? Assume the population’s diet contains an average BaP concentration of 15 mg/kg food and its per capita food consumption rate is 0.8 kg/day. Assume the average adult body weight is 60 kg.

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To compare the HED of 0.58 mg/kg-d with dietary BaP exposure, start by calculating the daily BaP intake from the diet. With an average BaP concentration of 15 mg/kg food and a daily food consumption of 0.8 kg, daily intake = 15 × 0.8 = 12 mg/day.
Next, convert this intake to a body-weight-normalized dose by dividing by the average adult body weight (60 kg): dietary exposure per kg body weight = 12 mg/day ÷ 60 kg = 0.2 mg/kg-d.
Now compare the two figures: HED = 0.58 mg/kg-d vs dietary exposure = 0.2 mg/kg-d. Dividing 0.58 by 0.2 yields 0.58 ÷ 0.2 = 2.9, which is approximately 3 times higher.
Thus, the HED of 0.58 mg/kg-d is about three times greater than the dietary BaP exposure calculated from the assumed diet and consumption parameters.
Regarding the answer options provided, there is only one choice: 'Rat study HED about 3x > dietary exposure.' The calculation above supports this statement in quantitative terms. If other options existed (e.g., values far from 3x, or directions such as HED being lower than dietary exposure), they would be inconsistent with the computed ratio of ~3.
Note: The reasoning assumes the provided dietary concentration, consumption rate, and body weight are representative for the population and that the HED is intended to be directly comparable to a daily dietary exposure on a per-kilogram basis.

EH 206 Homework 1

How does a HED of 0.58 mg/kg/d compare to BaP intake from food? Assume the population’s diet contains an average BaP concentration of 15 mg/kg food and its per capita food consumption rate is 0.8 kg/day. Assume the average adult body weight is 60 kg.

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