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Questions
Su25-STATS-141-01/BIO-141-01 5.1 & 5.2 Readiness Quiz
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Which variable would you regard as the explanatory variable and which as the response variable? 1: Sex Sex 2: Whether have broken up with someone digitally Whether have broken up with someone digitally
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Approach Analysis
Let's restate the setup: we have two variables and we need to decide which is explanatory (independent) and which is the response (dependent).
Option 1 corresponds to the variable 'Sex'. In many study designs, sex is treated as an independent characteristic that might influence outcomes, rather than being an outcome itself. Therefore, it ......Login to view full explanationLog in for full answers
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Question text The students below each construct a sinusoidal function based on a shared scenario involving water level fluctuations.Match each student’s reasoning to the explanation that best fits their thinking. Scenario:The depth of water , in metres, at a canal dock fluctuates due to the system of canal locks lowering and raising the water for container ships. The water varies sinusoidally from a minimum of 1.5 m to a maximum of 4.5 m. The depth reaches its minimum at 5:00 AM, and one full cycle of the water level is completed every 4 hours. The horizontal axis represents time , in hours, where corresponds to midnight. Student 1:I was asked to find the water depth at 3 AM.The equation I created was Since the minimum occurs at 5:00 AM, I shifted the function by 5.Using this function, I found the depth at 3 AM was 1.5 m.Answer 1 Question 22[select: , All parameters are correct. Therefore, the initial evaluation is correct, and the correct depth at 3 AM is 1.5 m. , All parameters are correct except the phase shift: there should be a phase shift of -5. Therefore, the initial evaluation is incorrect; using the new equation, the correct depth at 3 AM is 4.5 m. , All parameters are correct except the k-value: the k-value should be pi/4. The initial evaluation is still correct; the depth at 3 AM is 1.5 m.] Student 2:I was asked to find the water depth at 6 AM.The equation I created was I chose sine because the water starts rising after its lowest point.Using my equation, I found the depth at 6 AM was 3 m.Answer 2 Question 22[select: , All parameters are correct except for the amplitude, which should be negative. The initial evaluation is still correct; the depth at 6 AM is 3 m., All parameters are except the phase shift: there should be a phase shift of -5. Therefore, the initial evaluation is incorrect; using the new equation, the correct depth at 6 AM is 4.1 m., All parameters are correct except the k-value; the k-value should be pi/2. The initial evaluation is still correct; the depth at 6 AM is 3 m. ] Student 3:I was asked to find the water depth at 1 PM.The equation I created was Since the minimum occurs at 5:00 AM, I used a cosine function with a shift to match the point.I found the depth at 1 PM to be 4.5 m.Answer 3 Question 22[select: , All parameters are correct except the k-value; the correct k-value is pi/4. The initial evaluation is still correct; the depth at 1 PM is 4.5 m., All parameters are correct except for the phase shift; there should be a phase shift of -3. Therefore, the initial evaluation is incorrect; using the new equation, the correct depth at 1 PM is 1.5 m.. , All parameters are correct and the student’s evaluation of the depth was correct; the depth at 1 PM is 4.5 m.]
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