What will the following code output?

Question

BlackTom AI · Accepted Answer

We start by inspecting the given code snippet and its control flow.
Option 1: "abc" — This would be the input if int() were able to convert the string. Since the string "abc" is not a valid integer literal, the conversion would fail before any printing occurs. The code does not reach a simple print of the string unless conversion succeeds, so this choice misrepresents the actual runtime result.
Option 2: "Error" — This is a generic placeholder that doesn't match Python’s exception handling. The code uses a try/except that catches a specific exception type, not a generic error string, so a plain "Error" would not be produced by this program.
Option 3: "ValueError" — When int("abc") is executed, Python raises a ValueError because the string cannot be parsed as an integer. However, the provided code has an except block that handles ValueError and prints a different message, so no direct ValueError message is output.
Option 4: "Nothing" — This would imply that nothing is printed or that the program terminates without output. The except block is designed to print a message, so something will be printed unless an unhandled exception occurs. Therefore, this option does not reflect the actual behavior.
Option 5: "Invalid integer" — Inside the except ValueError block, the program prints the exact string "Invalid integer". Since the int("abc") call raises ValueError, control moves to the except block, and the message is produced. This aligns with the intended flow of exception handling.
Option 6: "0" — There is no code path that prints a numeric zero. The conversion fails, and the only print statement outputs the string from the except block, not a numeral.
In summary, the flow is: attempt to convert a non-numeric string to int → ValueError is raised → caught by ValueError handler → print "Invalid integer" → no other output is produced.

IS 4485-001 Fall 2025 Final Exam

What will the following code output?

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