If the equilibrium constants for the two reactions
2 HCl(g) ⇔H2(g) + Cl2(g)
and
I2(g) + Cl2(g) ⇔ 2 ICl(g)
are denoted K1 and K2 respectively, then the equilibrium constant for the reaction
2 HCl(g) + I2(g) ⇔ 2 ICl(g) + H2(g) equals

Question

If the equilibrium constants for the two reactions
2 HCl(g) ⇔H2(g) + Cl2(g)
and
I2(g) + Cl2(g) ⇔ 2 ICl(g)
are denoted K1 and K2 respectively, then the equilibrium constant for the reaction
2 HCl(g) + I2(g) ⇔ 2 ICl(g) + H2(g) equals

BlackTom AI · Accepted Answer

Let's restate the problem to ensure clarity: we are given two equilibrium reactions with their constants,

1) 2 HCl(g) ⇌ H2(g) + Cl2(g) with equilibrium constant K1,
2) I2(g) + Cl2(g) ⇌ 2 ICl(g) with equilibrium constant K2,

and we are asked for the equilibrium constant of the overall reaction
2 HCl(g) + I2(g) ⇌ 2 ICl(g) + H2(g).

First, look at how to obtain the overall reaction by combining the two given equilibria. If we take reaction 1 in its forward direction, we have:
2 HCl ⇌ H2 + Cl2.
If we also take reaction 2 in its forward direction, we have:
I2 + Cl2 ⇌ 2 ICl.
Adding these two balanced equations gives:
2 HCl + I2 + Cl2 ⇌ H2 + Cl2 + 2 ICl.
The Cl2 term appears on both sides and can be canceled, yielding:
2 HCl + I2 ⇌ H2 + 2 ICl,
which is the same as the target reaction (the order of products is not important).

If the equilibrium constants for the two reactions 2 HCl(g) ⇔H2(g) + Cl2(g) and I2(g) + Cl2(g) ⇔ 2 ICl(g) are denoted K1 and K2 respectively, then the equilibrium constant for the reaction 2 HCl(g) + I2(g) ⇔ 2 ICl(g) + H2(g) equals

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