Express the reverse equilibrium constant for the following reaction.

3 H2(g) + 3 Br2(g) 6 HBr(g)

Question

Express the reverse equilibrium constant for the following reaction.

3 H2(g) + 3 Br2(g)  6 HBr(g)

BlackTom AI · Accepted Answer

We are given the reaction: 3 H2(g) + 3 Br2(g) ⇌ 6 HBr(g) and asked for the reverse equilibrium constant.

First, recall how to write the equilibrium constant for a reaction in the forward direction. For aA + bB ⇌ cC, K_forward = [C]^c / ([A]^a [B]^b). Here, the forward reaction uses 3 H2 and 3 Br2 to form 6 HBr, so:
- A = H2 with a = 3
- B = Br2 with b = 3
- C = HBr with c = 6
Thus, K_forward = [HBr]^6 / ([H2]^3 [Br2]^3).

Now, the reverse reaction is the exact opposite: 6 HBr ⇌ 3 H2 + 3 Br2. The equilibrium constant for the reverse direction, K_reverse, is the reciprocal of the forward constant:
K_reverse = 1 / K_forward = ([H2]^3 [Br2]^3) / [HBr]^6.

To connect this to common answer formats, you can also think of K_reverse as:
K_reverse = ([H2]^3 [Br2]^3) / [HBr]^6 = ([H2]^3 [Br2]^3) × ([HBr]^{-6}).

Potential student pitfalls or misconceptions:
- Some students might mistakenly write the forward expression instead of the reciprocal for the reverse, which would give K_reverse = [HBr]^6 / ([H2]^3 [Br2]^3). Remember, the reverse constant is the reciprocal of the forward constant.
- Others might not apply the correct stoichiometric exponents. The exponents in the numerator correspond to the coefficients of the products in the reverse reaction (or the reactants in the forward reaction), and vice versa for the denominator.
- If options are written with simplified forms, make sure there’s no overlooked cancellation or factoring; the most compact and correct form here is the one with [H2]^3 [Br2]^3 in the numerator and [HBr]^6 in the denominator.

Because the provided answer options are not visible in the prompt, I cannot map these to specific letter choices. However, the correct conceptual form for the reverse equilibrium constant of the given reaction is K_reverse = ([H2]^3 [Br2]^3) / [HBr]^6, i.e., the reciprocal of the forward expression.

Express the reverse equilibrium constant for the following reaction. 3 H2(g) + 3 Br2(g) 6 HBr(g)

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